22=-4.9x^2+34x+80

Solution for 22=-4.9x^2+34x+80 equation:

22=-4.9x^2+34x+80

We move all terms to the left:

22-(-4.9x^2+34x+80)=0

We get rid of parentheses

4.9x^2-34x-80+22=0

We add all the numbers together, and all the variables

4.9x^2-34x-58=0

a = 4.9; b = -34; c = -58;
Δ = b2-4ac
Δ = -342-4·4.9·(-58)
Δ = 2292.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-\sqrt{2292.8}}{2*4.9}=\frac{34-\sqrt{2292.8}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+\sqrt{2292.8}}{2*4.9}=\frac{34+\sqrt{2292.8}}{9.8}
$